# Transfer frequency from inside the L so you can volume within the mL so the tools to have occurrence (grams mL -1 ) was uniform:

Transfer frequency from inside the L so you can volume within the mL so the tools to have occurrence (grams mL -1 ) was uniform:

(ii) Maybe you have utilized the right amount of significant numbers? density (1.03 ) provides 3 tall data regularity (1) have step 1 significant shape When multiplying otherwise dividing, how many extreme numbers regarding the outcome is the same because the minimum number of tall rates throughout the terms and conditions utilized, therefore we try justified in using step 1 extreme figure. The address (ten30) have cuatro tall data! Given that our company is simply warranted in using step one extreme figure, we could allow the answer given that a thousand grams, however the best solution is always to use medical notation and you can develop 1 ? ten 3 grams

(iii) Can be your answer possible? Do a good “rough” calculation: density ≈ step one grams mL -step one 1 mL out-of milk has actually scores of from the step 1 g 1 L (a thousand mL) out of dairy keeps quite a few on the one thousand ? step one = a lot of grams Since this rough calculation is nearly the cautiously computed really worth for bulk our company is reasonably certain that our respond to is correct.

Question 5. In the 25°C and you will step 1 automatic teller machine tension, diamond has a density off step three.5 grams cm -step 3 . Assess the quantity for the cm step three out-of 0.fifty g regarding diamond at twenty five°C and you will 1 automatic teller machine tension.

step 3.5 g cm -step three ? V (cm step three ) = V(cm step three ) ? 0.fifty g ? V (cm 3 ) step 3.5 grams cm -step 3 ? V (cm step three ) = 0.50 grams

[ step 3.5 g cm -step 3 ? V (cm 3 )] ? 3.5 escort review Torrance CA g cm -step three = 0.50 g ? step 3.5 grams cm -3 V (cm step 3 ) = 0.fifty ? step three.5 (cm -3 ) = 0.14 cm step three

## Perform good “rough” calculation: density ≈ 5 grams cm -3 step 1 cm -step 3 off diamond has a mass of regarding 5 grams

(ii) Perhaps you have made use of the proper level of tall data? density (step three.5) has actually 2 tall rates volume (0.50) features 2 tall numbers Whenever multiplying or separating, what amount of significant numbers on the outcome is a similar since the very least quantity of high numbers from the terms utilized, therefore we is actually justified in making use of dos high data. All of our address (0.14) possess 2 tall numbers

(iii) Is your answer plausible? 50 g for the mass which is 1 /10 th the mass of 1 cm -3 of diamond So the volume of 0.50 g of diamond will 1 /10 th the volume that is V = 1 /10 ? 1 cm 3 = 0.1 cm 3 Since this “rough” answer is about the same as our carefully calculated answer we are reasonably confident that our answer is correct.

Concern six. During the 25°C and you can 1 atm pressure, ethylene glycol has actually a thickness of 1.11 grams mL -step 1 . Estimate the amount from inside the mL off 0.025 kilogram away from ethylene glycol during the 25°C and you will step one atm stress.

Convert bulk in the kg to help you mass within the g so you can be consistent which have equipment out of thickness (grams mL -1 ):

V (mL) ? 1.11 (grams mL -step 1 ) = V (mL) ? twenty-five (g) ? V (mL) V (mL) ? step 1.eleven (g mL -1 ) = twenty five (g)

## Practical question gives us 0

[V (mL) ? step one.11 (g mL -step 1 ) ] ? step one.eleven (g mL -step 1 ) = twenty-five (g) ? step 1.11 ( g mL -step one ) V (mL) = 25 ? 1.11 (mL -step 1 ) = 23 mL

(ii) Perhaps you have made use of the right quantity of tall rates? bulk (0.025) possess 2 extreme figures occurrence (1.11) has step three tall figures When multiplying or isolating, the number of high data from the outcome is a similar just like the least level of extreme numbers in the conditions put, so we try warranted in making use of 2 tall figures. The respond to (25) enjoys dos high data